| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.25 |
| Score | 0% | 65% |
A tiger in a zoo has consumed 72 pounds of food in 6 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 156 pounds?
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| 7 | |
| 9 | |
| 1 |
If the tiger has consumed 72 pounds of food in 6 days that's \( \frac{72}{6} \) = 12 pounds of food per day. The tiger needs to consume 156 - 72 = 84 more pounds of food to reach 156 pounds total. At 12 pounds of food per day that's \( \frac{84}{12} \) = 7 more days.
What is \( \frac{1}{8} \) x \( \frac{4}{8} \)?
| \(\frac{1}{4}\) | |
| \(\frac{3}{10}\) | |
| \(\frac{1}{16}\) | |
| \(\frac{4}{15}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{8} \) x \( \frac{4}{8} \) = \( \frac{1 x 4}{8 x 8} \) = \( \frac{4}{64} \) = \(\frac{1}{16}\)
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
distributive |
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associative |
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PEDMAS |
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commutative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
8 members of a bridal party need transported to a wedding reception but there are only 3 2-passenger taxis available to take them. How many will need to find other transportation?
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There are 3 2-passenger taxis available so that's 3 x 2 = 6 total seats. There are 8 people needing transportation leaving 8 - 6 = 2 who will have to find other transportation.
What is \( \frac{7}{4} \) - \( \frac{7}{6} \)?
| \( \frac{8}{12} \) | |
| \(\frac{7}{12}\) | |
| 2 \( \frac{3}{12} \) | |
| \( \frac{4}{12} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 6 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{7 x 3}{4 x 3} \) - \( \frac{7 x 2}{6 x 2} \)
\( \frac{21}{12} \) - \( \frac{14}{12} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{21 - 14}{12} \) = \( \frac{7}{12} \) = \(\frac{7}{12}\)