| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.52 |
| Score | 0% | 70% |
If a car travels 100 miles in 2 hours, what is the average speed?
| 40 mph | |
| 50 mph | |
| 30 mph | |
| 20 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)13 members of a bridal party need transported to a wedding reception but there are only 2 5-passenger taxis available to take them. How many will need to find other transportation?
| 8 | |
| 4 | |
| 3 | |
| 6 |
There are 2 5-passenger taxis available so that's 2 x 5 = 10 total seats. There are 13 people needing transportation leaving 13 - 10 = 3 who will have to find other transportation.
A tiger in a zoo has consumed 112 pounds of food in 8 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 196 pounds?
| 1 | |
| 6 | |
| 4 | |
| 10 |
If the tiger has consumed 112 pounds of food in 8 days that's \( \frac{112}{8} \) = 14 pounds of food per day. The tiger needs to consume 196 - 112 = 84 more pounds of food to reach 196 pounds total. At 14 pounds of food per day that's \( \frac{84}{14} \) = 6 more days.
Solve for \( \frac{4!}{5!} \)
| 120 | |
| 6720 | |
| \( \frac{1}{5} \) | |
| 42 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{5!} \)
\( \frac{4 \times 3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5} \)
\( \frac{1}{5} \)
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 34 | |
| 38 | |
| 31 | |
| 30 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31