| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
Simplify \( \sqrt{12} \)
| 2\( \sqrt{3} \) | |
| 3\( \sqrt{6} \) | |
| 8\( \sqrt{3} \) | |
| 6\( \sqrt{6} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{12} \)
\( \sqrt{4 \times 3} \)
\( \sqrt{2^2 \times 3} \)
2\( \sqrt{3} \)
Simplify \( \frac{32}{56} \).
| \( \frac{3}{8} \) | |
| \( \frac{5}{14} \) | |
| \( \frac{4}{7} \) | |
| \( \frac{1}{3} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 56 are [1, 2, 4, 7, 8, 14, 28, 56]. They share 4 factors [1, 2, 4, 8] making 8 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{32}{56} \) = \( \frac{\frac{32}{8}}{\frac{56}{8}} \) = \( \frac{4}{7} \)
Alex loaned Monica $900 at an annual interest rate of 7%. If no payments are made, what is the total amount owed at the end of the first year?
| $963 | |
| $927 | |
| $918 | |
| $945 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $900
i = 0.07 x $900
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $900 + $63Solve for \( \frac{2!}{4!} \)
| \( \frac{1}{42} \) | |
| \( \frac{1}{12} \) | |
| 120 | |
| 336 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{2!}{4!} \)
\( \frac{2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4 \times 3} \)
\( \frac{1}{12} \)
What is \( 6 \)\( \sqrt{45} \) + \( 6 \)\( \sqrt{5} \)
| 12\( \sqrt{45} \) | |
| 36\( \sqrt{45} \) | |
| 12\( \sqrt{225} \) | |
| 24\( \sqrt{5} \) |
To add these radicals together their radicands must be the same:
6\( \sqrt{45} \) + 6\( \sqrt{5} \)
6\( \sqrt{9 \times 5} \) + 6\( \sqrt{5} \)
6\( \sqrt{3^2 \times 5} \) + 6\( \sqrt{5} \)
(6)(3)\( \sqrt{5} \) + 6\( \sqrt{5} \)
18\( \sqrt{5} \) + 6\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
18\( \sqrt{5} \) + 6\( \sqrt{5} \)