| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.86 |
| Score | 0% | 77% |
Simplify \( \frac{28}{68} \).
| \( \frac{4}{13} \) | |
| \( \frac{3}{5} \) | |
| \( \frac{7}{17} \) | |
| \( \frac{7}{15} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 68 are [1, 2, 4, 17, 34, 68]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{28}{68} \) = \( \frac{\frac{28}{4}}{\frac{68}{4}} \) = \( \frac{7}{17} \)
Solve for \( \frac{4!}{6!} \)
| \( \frac{1}{42} \) | |
| 336 | |
| 42 | |
| \( \frac{1}{30} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{6!} \)
\( \frac{4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5} \)
\( \frac{1}{30} \)
What is the distance in miles of a trip that takes 6 hours at an average speed of 55 miles per hour?
| 90 miles | |
| 330 miles | |
| 70 miles | |
| 50 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 55mph \times 6h \)
330 miles
How many hours does it take a car to travel 225 miles at an average speed of 25 miles per hour?
| 9 hours | |
| 2 hours | |
| 8 hours | |
| 4 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{225mi}{25mph} \)
9 hours
What is \( \sqrt{\frac{16}{16}} \)?
| 1\(\frac{2}{5}\) | |
| 1\(\frac{4}{5}\) | |
| 1 | |
| \(\frac{2}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{16}{16}} \)
\( \frac{\sqrt{16}}{\sqrt{16}} \)
\( \frac{\sqrt{4^2}}{\sqrt{4^2}} \)
1