ASVAB Arithmetic Reasoning Practice Test 199225 Results

Your Results Global Average
Questions 5 5
Correct 0 3.75
Score 0% 75%

Review

1

What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?

69% Answer Correctly
38
39
53
46

Solution

The equation for this sequence is:

an = an-1 + 3(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46


2

What is \( \frac{3}{7} \) ÷ \( \frac{1}{9} \)?

68% Answer Correctly
3\(\frac{6}{7}\)
\(\frac{1}{30}\)
\(\frac{1}{10}\)
\(\frac{1}{15}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{3}{7} \) ÷ \( \frac{1}{9} \) = \( \frac{3}{7} \) x \( \frac{9}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{7} \) x \( \frac{9}{1} \) = \( \frac{3 x 9}{7 x 1} \) = \( \frac{27}{7} \) = 3\(\frac{6}{7}\)


3

Which of the following is a mixed number?

82% Answer Correctly

\({7 \over 5} \)

\(1 {2 \over 5} \)

\({5 \over 7} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

How many 12-passenger vans will it take to drive all 32 members of the football team to an away game?

81% Answer Correctly
3 vans
9 vans
14 vans
4 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{32}{12} \) = 2\(\frac{2}{3}\)

So, it will take 2 full vans and one partially full van to transport the entire team making a total of 3 vans.


5

What is -3c4 x 6c3?

75% Answer Correctly
-18c7
3c4
-18c-1
3c3

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-3c4 x 6c3
(-3 x 6)c(4 + 3)
-18c7