| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
The __________ is the greatest factor that divides two integers.
least common multiple |
|
absolute value |
|
greatest common multiple |
|
greatest common factor |
The greatest common factor (GCF) is the greatest factor that divides two integers.
Which of the following is not a prime number?
7 |
|
2 |
|
9 |
|
5 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
What is -4b6 + 6b6?
| 10b6 | |
| -10b6 | |
| 2b6 | |
| 10b-6 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-4b6 + 6b6
(-4 + 6)b6
2b6
What is \( \frac{30\sqrt{8}}{6\sqrt{4}} \)?
| 2 \( \sqrt{\frac{1}{5}} \) | |
| \(\frac{1}{2}\) \( \sqrt{\frac{1}{5}} \) | |
| 5 \( \sqrt{2} \) | |
| \(\frac{1}{5}\) \( \sqrt{\frac{1}{2}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{30\sqrt{8}}{6\sqrt{4}} \)
\( \frac{30}{6} \) \( \sqrt{\frac{8}{4}} \)
5 \( \sqrt{2} \)
A machine in a factory has an error rate of 6 parts per 100. The machine normally runs 24 hours a day and produces 8 parts per hour. Yesterday the machine was shut down for 8 hours for maintenance.
How many error-free parts did the machine produce yesterday?
| 159 | |
| 120.3 | |
| 131 | |
| 108.3 |
The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:
\( \frac{6}{100} \) x 8 = \( \frac{6 \times 8}{100} \) = \( \frac{48}{100} \) = 0.48 errors per hour
So, in an average hour, the machine will produce 8 - 0.48 = 7.52 error free parts.
The machine ran for 24 - 8 = 16 hours yesterday so you would expect that 16 x 7.52 = 120.3 error free parts were produced yesterday.