To find the average of these 4 numbers add them together then divide by 4:

\( \frac{15 + 13 + 15 + 13}{4} \) = \( \frac{56}{4} \) = 14

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

42,000 fans x \( \frac{5}{6} \) = \( \frac{210000}{6} \) = 35,000 fans.

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (3 + 5) ÷ 4 x 2 - 3²
P: 4 + (8) ÷ 4 x 2 - 3²
E: 4 + 8 ÷ 4 x 2 - 9
MD: 4 + \( \frac{8}{4} \) x 2 - 9
MD: 4 + \( \frac{16}{4} \) - 9
AS: \( \frac{16}{4} \) + \( \frac{16}{4} \) - 9
AS: \( \frac{32}{4} \) - 9
AS: \( \frac{32 - 36}{4} \)
\( \frac{-4}{4} \)
-1

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 6 meters so the equation becomes: 2w + 2h = 6.

Putting these two equations together and solving for width (w):

2w + 2h = 6
w + h = \( \frac{6}{2} \)
w + h = 3
w = 3 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 3 - 2w
3w = 3
w = \( \frac{3}{3} \)
w = 1

Since h = 2w that makes h = (2 x 1) = 2 and the area = h x w = 1 x 2 = 2 m²