| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.26 |
| Score | 0% | 65% |
What is -b4 - 3b4?
| -4b4 | |
| -4b-4 | |
| 4b4 | |
| 2b4 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:
-1b4 - 3b4
(-1 - 3)b4
-4b4
How many 10-passenger vans will it take to drive all 86 members of the football team to an away game?
| 6 vans | |
| 4 vans | |
| 7 vans | |
| 9 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{86}{10} \) = 8\(\frac{3}{5}\)
So, it will take 8 full vans and one partially full van to transport the entire team making a total of 9 vans.
What is \( 3 \)\( \sqrt{75} \) - \( 7 \)\( \sqrt{3} \)
| -4\( \sqrt{75} \) | |
| 21\( \sqrt{75} \) | |
| -4\( \sqrt{25} \) | |
| 8\( \sqrt{3} \) |
To subtract these radicals together their radicands must be the same:
3\( \sqrt{75} \) - 7\( \sqrt{3} \)
3\( \sqrt{25 \times 3} \) - 7\( \sqrt{3} \)
3\( \sqrt{5^2 \times 3} \) - 7\( \sqrt{3} \)
(3)(5)\( \sqrt{3} \) - 7\( \sqrt{3} \)
15\( \sqrt{3} \) - 7\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
15\( \sqrt{3} \) - 7\( \sqrt{3} \)Which of the following is a mixed number?
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
|
\({5 \over 7} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
If the ratio of home fans to visiting fans in a crowd is 4:1 and all 32,000 seats in a stadium are filled, how many home fans are in attendance?
| 37,500 | |
| 25,600 | |
| 32,000 | |
| 35,250 |
A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:
32,000 fans x \( \frac{4}{5} \) = \( \frac{128000}{5} \) = 25,600 fans.