ASVAB Arithmetic Reasoning Practice Test 204259 Results

Your Results Global Average
Questions 5 5
Correct 0 3.31
Score 0% 66%

Review

1

Find the average of the following numbers: 13, 5, 13, 5.

74% Answer Correctly
9
8
11
6

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{13 + 5 + 13 + 5}{4} \) = \( \frac{36}{4} \) = 9


2

What is the next number in this sequence: 1, 9, 17, 25, 33, __________ ?

92% Answer Correctly
34
47
49
41

Solution

The equation for this sequence is:

an = an-1 + 8

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 8
a6 = 33 + 8
a6 = 41


3

What is (z4)4?

79% Answer Correctly
z0
z8
z16
4z4

Solution

To raise a term with an exponent to another exponent, retain the base and multiply the exponents:

(z4)4
z(4 * 4)
z16


4

What is \( 3 \)\( \sqrt{75} \) + \( 6 \)\( \sqrt{3} \)

35% Answer Correctly
18\( \sqrt{75} \)
18\( \sqrt{25} \)
18\( \sqrt{225} \)
21\( \sqrt{3} \)

Solution

To add these radicals together their radicands must be the same:

3\( \sqrt{75} \) + 6\( \sqrt{3} \)
3\( \sqrt{25 \times 3} \) + 6\( \sqrt{3} \)
3\( \sqrt{5^2 \times 3} \) + 6\( \sqrt{3} \)
(3)(5)\( \sqrt{3} \) + 6\( \sqrt{3} \)
15\( \sqrt{3} \) + 6\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

15\( \sqrt{3} \) + 6\( \sqrt{3} \)
(15 + 6)\( \sqrt{3} \)
21\( \sqrt{3} \)


5

A machine in a factory has an error rate of 7 parts per 100. The machine normally runs 24 hours a day and produces 6 parts per hour. Yesterday the machine was shut down for 2 hours for maintenance.

How many error-free parts did the machine produce yesterday?

49% Answer Correctly
156.2
117.8
122.8
139.2

Solution

The hourly error rate for this machine is the error rate in parts per 100 multiplied by the number of parts produced per hour:

\( \frac{7}{100} \) x 6 = \( \frac{7 \times 6}{100} \) = \( \frac{42}{100} \) = 0.42 errors per hour

So, in an average hour, the machine will produce 6 - 0.42 = 5.58 error free parts.

The machine ran for 24 - 2 = 22 hours yesterday so you would expect that 22 x 5.58 = 122.8 error free parts were produced yesterday.