ASVAB Arithmetic Reasoning Practice Test 204296 Results

Your Results Global Average
Questions 5 5
Correct 0 3.23
Score 0% 65%

Review

1

If all of a roofing company's 6 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 4 complete crews out on jobs?

55% Answer Correctly
6
3
2
4

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 2 crews so there are \( \frac{6}{2} \) = 3 workers on a crew. 4 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 4 x 3 = 12 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 12 - 6 = 6 new staff for the busy season.


2

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = 7 or a = -7

none of these is correct

a = 7

a = -7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


3

What is \( 8 \)\( \sqrt{18} \) + \( 7 \)\( \sqrt{2} \)

35% Answer Correctly
56\( \sqrt{9} \)
56\( \sqrt{18} \)
31\( \sqrt{2} \)
15\( \sqrt{2} \)

Solution

To add these radicals together their radicands must be the same:

8\( \sqrt{18} \) + 7\( \sqrt{2} \)
8\( \sqrt{9 \times 2} \) + 7\( \sqrt{2} \)
8\( \sqrt{3^2 \times 2} \) + 7\( \sqrt{2} \)
(8)(3)\( \sqrt{2} \) + 7\( \sqrt{2} \)
24\( \sqrt{2} \) + 7\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

24\( \sqrt{2} \) + 7\( \sqrt{2} \)
(24 + 7)\( \sqrt{2} \)
31\( \sqrt{2} \)


4

Which of the following is a mixed number?

82% Answer Correctly

\({5 \over 7} \)

\(1 {2 \over 5} \)

\({a \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


5

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

fraction

integer

mixed number

improper fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.