| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.91 |
| Score | 0% | 58% |
What is \( \frac{8}{2} \) - \( \frac{4}{10} \)?
| 2 \( \frac{5}{13} \) | |
| \( \frac{8}{14} \) | |
| 3\(\frac{3}{5}\) | |
| \( \frac{1}{10} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [10, 20, 30, 40, 50] making 10 the smallest multiple 2 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 5}{2 x 5} \) - \( \frac{4 x 1}{10 x 1} \)
\( \frac{40}{10} \) - \( \frac{4}{10} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{40 - 4}{10} \) = \( \frac{36}{10} \) = 3\(\frac{3}{5}\)
Solve 2 + (2 + 5) ÷ 5 x 3 - 32
| -2\(\frac{4}{5}\) | |
| \(\frac{3}{8}\) | |
| 4\(\frac{1}{2}\) | |
| 1 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
2 + (2 + 5) ÷ 5 x 3 - 32
P: 2 + (7) ÷ 5 x 3 - 32
E: 2 + 7 ÷ 5 x 3 - 9
MD: 2 + \( \frac{7}{5} \) x 3 - 9
MD: 2 + \( \frac{21}{5} \) - 9
AS: \( \frac{10}{5} \) + \( \frac{21}{5} \) - 9
AS: \( \frac{31}{5} \) - 9
AS: \( \frac{31 - 45}{5} \)
\( \frac{-14}{5} \)
-2\(\frac{4}{5}\)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 45% off." If Damon buys two shirts, each with a regular price of $48, how much will he pay for both shirts?
| $50.40 | |
| $69.60 | |
| $74.40 | |
| $60.00 |
By buying two shirts, Damon will save $48 x \( \frac{45}{100} \) = \( \frac{$48 x 45}{100} \) = \( \frac{$2160}{100} \) = $21.60 on the second shirt.
So, his total cost will be
$48.00 + ($48.00 - $21.60)
$48.00 + $26.40
$74.40
If a rectangle is twice as long as it is wide and has a perimeter of 54 meters, what is the area of the rectangle?
| 8 m2 | |
| 162 m2 | |
| 18 m2 | |
| 128 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.
Putting these two equations together and solving for width (w):
2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9
Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m2
What is \( \frac{2}{8} \) x \( \frac{3}{7} \)?
| \(\frac{3}{28}\) | |
| \(\frac{1}{10}\) | |
| \(\frac{6}{7}\) | |
| \(\frac{1}{20}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{8} \) x \( \frac{3}{7} \) = \( \frac{2 x 3}{8 x 7} \) = \( \frac{6}{56} \) = \(\frac{3}{28}\)