The equation for this sequence is:

a_n = a_n-1 + 3(n - 1)

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 3(6 - 1)
a₆ = 31 + 3(5)
a₆ = 46

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 7}{3 x 7} \) - \( \frac{3 x 3}{7 x 3} \)

\( \frac{14}{21} \) - \( \frac{9}{21} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{14 - 9}{21} \) = \( \frac{5}{21} \) = \(\frac{5}{21}\)

By buying two shirts, Ezra will save $39 x \( \frac{15}{100} \) = \( \frac{$39 x 15}{100} \) = \( \frac{$585}{100} \) = $5.85 on the second shirt.

So, his total cost will be
$39.00 + ($39.00 - $5.85)
$39.00 + $33.15
$72.15

First, solve for \( \left|x + 7\right| \):

\( \left|x + 7\right| \) + 0 = 9
\( \left|x + 7\right| \) = 9 + 0
\( \left|x + 7\right| \) = 9

The value inside the absolute value brackets can be either positive or negative so (x + 7) must equal + 9 or -9 for \( \left|x + 7\right| \) to equal 9:

So, x = -16 or x = 2.

An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.