| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.78 |
| Score | 0% | 56% |
A circular logo is enlarged to fit the lid of a jar. The new diameter is 75% larger than the original. By what percentage has the area of the logo increased?
| 25% | |
| 15% | |
| 20% | |
| 37\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 75% the radius (and, consequently, the total area) increases by \( \frac{75\text{%}}{2} \) = 37\(\frac{1}{2}\)%
What is \( \frac{12\sqrt{40}}{6\sqrt{8}} \)?
| 2 \( \sqrt{\frac{1}{5}} \) | |
| \(\frac{1}{5}\) \( \sqrt{2} \) | |
| 2 \( \sqrt{5} \) | |
| \(\frac{1}{5}\) \( \sqrt{\frac{1}{2}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{12\sqrt{40}}{6\sqrt{8}} \)
\( \frac{12}{6} \) \( \sqrt{\frac{40}{8}} \)
2 \( \sqrt{5} \)
On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 10 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 17 | |
| 10 | |
| 13 | |
| 24 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{50}{100} \) = \( \frac{50 x 10}{100} \) = \( \frac{500}{100} \) = 5 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{5}{\frac{30}{100}} \) = 5 x \( \frac{100}{30} \) = \( \frac{5 x 100}{30} \) = \( \frac{500}{30} \) = 17 shots
to make the same number of shots as the guard and thus score the same number of points.
How many 2 gallon cans worth of fuel would you need to pour into an empty 20 gallon tank to fill it exactly halfway?
| 5 | |
| 10 | |
| 5 | |
| 9 |
To fill a 20 gallon tank exactly halfway you'll need 10 gallons of fuel. Each fuel can holds 2 gallons so:
cans = \( \frac{10 \text{ gallons}}{2 \text{ gallons}} \) = 5
If \( \left|y - 6\right| \) - 6 = 2, which of these is a possible value for y?
| -5 | |
| -8 | |
| 6 | |
| -2 |
First, solve for \( \left|y - 6\right| \):
\( \left|y - 6\right| \) - 6 = 2
\( \left|y - 6\right| \) = 2 + 6
\( \left|y - 6\right| \) = 8
The value inside the absolute value brackets can be either positive or negative so (y - 6) must equal + 8 or -8 for \( \left|y - 6\right| \) to equal 8:
| y - 6 = 8 y = 8 + 6 y = 14 | y - 6 = -8 y = -8 + 6 y = -2 |
So, y = -2 or y = 14.