| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.29 |
| Score | 0% | 66% |
On average, the center for a basketball team hits 40% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 12 | |
| 15 | |
| 27 | |
| 25 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{45}{100} \) = \( \frac{45 x 15}{100} \) = \( \frac{675}{100} \) = 6 shots
The center makes 40% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{6}{\frac{40}{100}} \) = 6 x \( \frac{100}{40} \) = \( \frac{6 x 100}{40} \) = \( \frac{600}{40} \) = 15 shots
to make the same number of shots as the guard and thus score the same number of points.
Solve for \( \frac{3!}{4!} \)
| 6720 | |
| \( \frac{1}{4} \) | |
| \( \frac{1}{72} \) | |
| 210 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)
What is 8b5 x 7b3?
| 56b15 | |
| 56b8 | |
| 56b3 | |
| 15b15 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
8b5 x 7b3
(8 x 7)b(5 + 3)
56b8
Which of the following is a mixed number?
\({7 \over 5} \) |
|
\({5 \over 7} \) |
|
\(1 {2 \over 5} \) |
|
\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
The total water usage for a city is 30,000 gallons each day. Of that total, 33% is for personal use and 56% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 6,300 | |
| 6,900 | |
| 1,500 | |
| 8,000 |
56% of the water consumption is industrial use and 33% is personal use so (56% - 33%) = 23% more water is used for industrial purposes. 30,000 gallons are consumed daily so industry consumes \( \frac{23}{100} \) x 30,000 gallons = 6,900 gallons.