To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{25}{36}} \)
\( \frac{\sqrt{25}}{\sqrt{36}} \)
\( \frac{\sqrt{5^2}}{\sqrt{6^2}} \)
\(\frac{5}{6}\)

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 4 and 8 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{3 x 2}{4 x 2} \) + \( \frac{3 x 1}{8 x 1} \)

\( \frac{6}{8} \) + \( \frac{3}{8} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{6 + 3}{8} \) = \( \frac{9}{8} \) = 1\(\frac{1}{8}\)

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 2 crews so there are \( \frac{8}{2} \) = 4 workers on a crew. 4 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 4 x 4 = 16 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 16 - 8 = 8 new staff for the busy season.

First, solve for \( \left|y - 2\right| \):

\( \left|y - 2\right| \) + 4 = 1
\( \left|y - 2\right| \) = 1 - 4
\( \left|y - 2\right| \) = -3

The value inside the absolute value brackets can be either positive or negative so (y - 2) must equal - 3 or --3 for \( \left|y - 2\right| \) to equal -3:

So, y = 5 or y = -1.

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 have in common.