ASVAB Arithmetic Reasoning Practice Test 219491 Results

Your Results Global Average
Questions 5 5
Correct 0 3.57
Score 0% 71%

Review

1

How many 12-passenger vans will it take to drive all 93 members of the football team to an away game?

80% Answer Correctly
6 vans
8 vans
4 vans
7 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{93}{12} \) = 7\(\frac{3}{4}\)

So, it will take 7 full vans and one partially full van to transport the entire team making a total of 8 vans.


2

Find the average of the following numbers: 9, 7, 12, 4.

74% Answer Correctly
8
13
12
4

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{9 + 7 + 12 + 4}{4} \) = \( \frac{32}{4} \) = 8


3

Convert 0.0007938 to scientific notation.

62% Answer Correctly
7.938 x 10-4
7.938 x 104
0.794 x 10-3
7.938 x 105

Solution

A number in scientific notation has the format 0.000 x 10exponent. To convert to scientific notation, move the decimal point to the right or the left until the number is a decimal between 1 and 10. The exponent of the 10 is the number of places you moved the decimal point and is positive if you moved the decimal point to the left and negative if you moved it to the right:

0.0007938 in scientific notation is 7.938 x 10-4


4

What is \( \sqrt{\frac{49}{25}} \)?

70% Answer Correctly
1\(\frac{3}{5}\)
\(\frac{2}{3}\)
1\(\frac{2}{5}\)
2\(\frac{2}{3}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{25}} \)
\( \frac{\sqrt{49}}{\sqrt{25}} \)
\( \frac{\sqrt{7^2}}{\sqrt{5^2}} \)
\( \frac{7}{5} \)
1\(\frac{2}{5}\)


5

What is \( \frac{10\sqrt{35}}{5\sqrt{7}} \)?

71% Answer Correctly
\(\frac{1}{5}\) \( \sqrt{2} \)
\(\frac{1}{2}\) \( \sqrt{5} \)
\(\frac{1}{5}\) \( \sqrt{\frac{1}{2}} \)
2 \( \sqrt{5} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{10\sqrt{35}}{5\sqrt{7}} \)
\( \frac{10}{5} \) \( \sqrt{\frac{35}{7}} \)
2 \( \sqrt{5} \)