| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
Latoya scored 78% on her final exam. If each question was worth 3 points and there were 270 possible points on the exam, how many questions did Latoya answer correctly?
| 66 | |
| 70 | |
| 55 | |
| 72 |
Latoya scored 78% on the test meaning she earned 78% of the possible points on the test. There were 270 possible points on the test so she earned 270 x 0.78 = 210 points. Each question is worth 3 points so she got \( \frac{210}{3} \) = 70 questions right.
Simplify \( \frac{36}{48} \).
| \( \frac{3}{4} \) | |
| \( \frac{9}{14} \) | |
| \( \frac{1}{3} \) | |
| \( \frac{5}{14} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 36 are [1, 2, 3, 4, 6, 9, 12, 18, 36] and the factors of 48 are [1, 2, 3, 4, 6, 8, 12, 16, 24, 48]. They share 6 factors [1, 2, 3, 4, 6, 12] making 12 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{36}{48} \) = \( \frac{\frac{36}{12}}{\frac{48}{12}} \) = \( \frac{3}{4} \)
What is 4\( \sqrt{7} \) x 5\( \sqrt{8} \)?
| 20\( \sqrt{8} \) | |
| 40\( \sqrt{14} \) | |
| 9\( \sqrt{7} \) | |
| 20\( \sqrt{15} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
4\( \sqrt{7} \) x 5\( \sqrt{8} \)
(4 x 5)\( \sqrt{7 \times 8} \)
20\( \sqrt{56} \)
Now we need to simplify the radical:
20\( \sqrt{56} \)
20\( \sqrt{14 \times 4} \)
20\( \sqrt{14 \times 2^2} \)
(20)(2)\( \sqrt{14} \)
40\( \sqrt{14} \)
Roger loaned Bob $300 at an annual interest rate of 7%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $64 | |
| $21 | |
| $84 | |
| $22 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $300
i = 0.07 x $300
i = $21
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 46 | |
| 37 | |
| 43 | |
| 50 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46