guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{35}{100} \) = \( \frac{35 x 25}{100} \) = \( \frac{875}{100} \) = 8 shots

The center makes 30% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{8}{\frac{30}{100}} \) = 8 x \( \frac{100}{30} \) = \( \frac{8 x 100}{30} \) = \( \frac{800}{30} \) = 27 shots

to make the same number of shots as the guard and thus score the same number of points.

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{35\sqrt{18}}{7\sqrt{9}} \)
\( \frac{35}{7} \) \( \sqrt{\frac{18}{9}} \)
5 \( \sqrt{2} \)

To subtract these radicals together their radicands must be the same:

8\( \sqrt{18} \) - 2\( \sqrt{2} \)
8\( \sqrt{9 \times 2} \) - 2\( \sqrt{2} \)
8\( \sqrt{3^2 \times 2} \) - 2\( \sqrt{2} \)
(8)(3)\( \sqrt{2} \) - 2\( \sqrt{2} \)
24\( \sqrt{2} \) - 2\( \sqrt{2} \)

Now that the radicands are identical, you can subtract them:

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 42 meters so the equation becomes: 2w + 2h = 42.

Putting these two equations together and solving for width (w):

2w + 2h = 42
w + h = \( \frac{42}{2} \)
w + h = 21
w = 21 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 21 - 2w
3w = 21
w = \( \frac{21}{3} \)
w = 7

Since h = 2w that makes h = (2 x 7) = 14 and the area = h x w = 7 x 14 = 98 m²

By buying two shirts, Roger will save $10 x \( \frac{10}{100} \) = \( \frac{$10 x 10}{100} \) = \( \frac{$100}{100} \) = $1.00 on the second shirt.