ASVAB Arithmetic Reasoning Practice Test 226302 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

What is the least common multiple of 3 and 9?

72% Answer Correctly
8
9
3
14

Solution

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 have in common.


2

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

integer

mixed number

fraction

improper fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


3

What is \( \frac{1}{8} \) ÷ \( \frac{1}{7} \)?

68% Answer Correctly
\(\frac{7}{8}\)
\(\frac{6}{35}\)
\(\frac{3}{14}\)
7

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{1}{8} \) ÷ \( \frac{1}{7} \) = \( \frac{1}{8} \) x \( \frac{7}{1} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{8} \) x \( \frac{7}{1} \) = \( \frac{1 x 7}{8 x 1} \) = \( \frac{7}{8} \) = \(\frac{7}{8}\)


4

A triathlon course includes a 100m swim, a 50.5km bike ride, and a 8.1km run. What is the total length of the race course?

69% Answer Correctly
59.1km
58.7km
48km
48.4km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.1km + 50.5km + 8.1km
total distance = 58.7km


5

What is \( 3 \)\( \sqrt{45} \) + \( 4 \)\( \sqrt{5} \)

35% Answer Correctly
7\( \sqrt{9} \)
13\( \sqrt{5} \)
12\( \sqrt{225} \)
7\( \sqrt{5} \)

Solution

To add these radicals together their radicands must be the same:

3\( \sqrt{45} \) + 4\( \sqrt{5} \)
3\( \sqrt{9 \times 5} \) + 4\( \sqrt{5} \)
3\( \sqrt{3^2 \times 5} \) + 4\( \sqrt{5} \)
(3)(3)\( \sqrt{5} \) + 4\( \sqrt{5} \)
9\( \sqrt{5} \) + 4\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

9\( \sqrt{5} \) + 4\( \sqrt{5} \)
(9 + 4)\( \sqrt{5} \)
13\( \sqrt{5} \)