ASVAB Arithmetic Reasoning Practice Test 228030 Results

Your Results Global Average
Questions 5 5
Correct 0 3.18
Score 0% 64%

Review

1

What is 4c2 x c7?

75% Answer Correctly
4c14
4c7
5c9
4c9

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

4c2 x c7
(4 x 1)c(2 + 7)
4c9


2

Which of the following is an improper fraction?

70% Answer Correctly

\({2 \over 5} \)

\(1 {2 \over 5} \)

\({a \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


3

What is \( 3 \)\( \sqrt{80} \) + \( 4 \)\( \sqrt{5} \)

35% Answer Correctly
7\( \sqrt{5} \)
16\( \sqrt{5} \)
7\( \sqrt{80} \)
12\( \sqrt{16} \)

Solution

To add these radicals together their radicands must be the same:

3\( \sqrt{80} \) + 4\( \sqrt{5} \)
3\( \sqrt{16 \times 5} \) + 4\( \sqrt{5} \)
3\( \sqrt{4^2 \times 5} \) + 4\( \sqrt{5} \)
(3)(4)\( \sqrt{5} \) + 4\( \sqrt{5} \)
12\( \sqrt{5} \) + 4\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

12\( \sqrt{5} \) + 4\( \sqrt{5} \)
(12 + 4)\( \sqrt{5} \)
16\( \sqrt{5} \)


4

Find the average of the following numbers: 16, 12, 16, 12.

74% Answer Correctly
14
10
19
12

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{16 + 12 + 16 + 12}{4} \) = \( \frac{56}{4} \) = 14


5

A bread recipe calls for 3\(\frac{1}{4}\) cups of flour. If you only have \(\frac{5}{8}\) cup, how much more flour is needed?

62% Answer Correctly
2\(\frac{1}{2}\) cups
2\(\frac{5}{8}\) cups
1\(\frac{1}{4}\) cups
3\(\frac{1}{4}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{4}\) - \(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{26}{8} \) - \( \frac{5}{8} \)) cups
\( \frac{21}{8} \) cups
2\(\frac{5}{8}\) cups