| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
The total water usage for a city is 45,000 gallons each day. Of that total, 21% is for personal use and 31% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 8,050 | |
| 900 | |
| 2,550 | |
| 4,500 |
31% of the water consumption is industrial use and 21% is personal use so (31% - 21%) = 10% more water is used for industrial purposes. 45,000 gallons are consumed daily so industry consumes \( \frac{10}{100} \) x 45,000 gallons = 4,500 gallons.
What is \( \sqrt{\frac{9}{49}} \)?
| \(\frac{5}{7}\) | |
| \(\frac{2}{3}\) | |
| \(\frac{3}{7}\) | |
| \(\frac{5}{6}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{9}{49}} \)
\( \frac{\sqrt{9}}{\sqrt{49}} \)
\( \frac{\sqrt{3^2}}{\sqrt{7^2}} \)
\(\frac{3}{7}\)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?
| 35% | |
| 15% | |
| 20% | |
| 30% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%
How many hours does it take a car to travel 150 miles at an average speed of 50 miles per hour?
| 3 hours | |
| 2 hours | |
| 1 hour | |
| 4 hours |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for time:
time = \( \frac{\text{distance}}{\text{speed}} \)
time = \( \frac{150mi}{50mph} \)
3 hours
Convert x-4 to remove the negative exponent.
| \( \frac{1}{x^4} \) | |
| \( \frac{-1}{x^{-4}} \) | |
| \( \frac{-1}{-4x} \) | |
| \( \frac{-4}{-x} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.