| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
If the ratio of home fans to visiting fans in a crowd is 2:1 and all 41,000 seats in a stadium are filled, how many home fans are in attendance?
| 36,000 | |
| 24,667 | |
| 27,333 | |
| 24,000 |
A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:
41,000 fans x \( \frac{2}{3} \) = \( \frac{82000}{3} \) = 27,333 fans.
Convert x-5 to remove the negative exponent.
| \( \frac{5}{x} \) | |
| \( \frac{-1}{-5x^{5}} \) | |
| \( \frac{-5}{-x} \) | |
| \( \frac{1}{x^5} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Bob loaned Ezra $1,500 at an annual interest rate of 2%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $6 | |
| $9 | |
| $30 | |
| $2 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,500
i = 0.02 x $1,500
i = $30
Simplify \( \frac{36}{64} \).
| \( \frac{1}{2} \) | |
| \( \frac{2}{5} \) | |
| \( \frac{5}{19} \) | |
| \( \frac{9}{16} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 36 are [1, 2, 3, 4, 6, 9, 12, 18, 36] and the factors of 64 are [1, 2, 4, 8, 16, 32, 64]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{36}{64} \) = \( \frac{\frac{36}{4}}{\frac{64}{4}} \) = \( \frac{9}{16} \)
What is \( \frac{-3x^7}{9x^4} \)?
| -\(\frac{1}{3}\)x3 | |
| -\(\frac{1}{3}\)x-3 | |
| -3x-3 | |
| -\(\frac{1}{3}\)x11 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-3x^7}{9x^4} \)
\( \frac{-3}{9} \) x(7 - 4)
-\(\frac{1}{3}\)x3