To subtract these radicals together their radicands must be the same:

4\( \sqrt{175} \) - 4\( \sqrt{7} \)
4\( \sqrt{25 \times 7} \) - 4\( \sqrt{7} \)
4\( \sqrt{5^2 \times 7} \) - 4\( \sqrt{7} \)
(4)(5)\( \sqrt{7} \) - 4\( \sqrt{7} \)
20\( \sqrt{7} \) - 4\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{70}{100} \) = \( \frac{70 x 10}{100} \) = \( \frac{700}{100} \) = 7 shots

The center makes 50% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{7}{\frac{50}{100}} \) = 7 x \( \frac{100}{50} \) = \( \frac{7 x 100}{50} \) = \( \frac{700}{50} \) = 14 shots

to make the same number of shots as the guard and thus score the same number of points.

If the tiger has consumed 24 pounds of food in 4 days that's \( \frac{24}{4} \) = 6 pounds of food per day. The tiger needs to consume 66 - 24 = 42 more pounds of food to reach 66 pounds total. At 6 pounds of food per day that's \( \frac{42}{6} \) = 7 more days.

By buying two shirts, Monty will save $48 x \( \frac{40}{100} \) = \( \frac{$48 x 40}{100} \) = \( \frac{$1920}{100} \) = $19.20 on the second shirt.