| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.71 |
| Score | 0% | 54% |
If a rectangle is twice as long as it is wide and has a perimeter of 24 meters, what is the area of the rectangle?
| 2 m2 | |
| 32 m2 | |
| 162 m2 | |
| 128 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.
Putting these two equations together and solving for width (w):
2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4
Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m2
How many 2\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 20 gallon tank to fill it exactly halfway?
| 9 | |
| 5 | |
| 4 | |
| 8 |
To fill a 20 gallon tank exactly halfway you'll need 10 gallons of fuel. Each fuel can holds 2\(\frac{1}{2}\) gallons so:
cans = \( \frac{10 \text{ gallons}}{2\frac{1}{2} \text{ gallons}} \) = 4
If the ratio of home fans to visiting fans in a crowd is 3:1 and all 37,000 seats in a stadium are filled, how many home fans are in attendance?
| 36,000 | |
| 27,750 | |
| 25,000 | |
| 33,333 |
A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:
37,000 fans x \( \frac{3}{4} \) = \( \frac{111000}{4} \) = 27,750 fans.
If there were a total of 250 raffle tickets sold and you bought 20 tickets, what's the probability that you'll win the raffle?
| 13% | |
| 16% | |
| 15% | |
| 8% |
You have 20 out of the total of 250 raffle tickets sold so you have a (\( \frac{20}{250} \)) x 100 = \( \frac{20 \times 100}{250} \) = \( \frac{2000}{250} \) = 8% chance to win the raffle.
A bread recipe calls for 3\(\frac{1}{4}\) cups of flour. If you only have \(\frac{1}{2}\) cup, how much more flour is needed?
| 3\(\frac{1}{8}\) cups | |
| 2\(\frac{3}{4}\) cups | |
| 3\(\frac{1}{4}\) cups | |
| 2\(\frac{1}{4}\) cups |
The amount of flour you need is (3\(\frac{1}{4}\) - \(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{26}{8} \) - \( \frac{4}{8} \)) cups
\( \frac{22}{8} \) cups
2\(\frac{3}{4}\) cups