| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.29 |
| Score | 0% | 66% |
What is \( \frac{3y^8}{5y^3} \)?
| \(\frac{3}{5}\)y5 | |
| \(\frac{3}{5}\)y2\(\frac{2}{3}\) | |
| 1\(\frac{2}{3}\)y5 | |
| 1\(\frac{2}{3}\)y11 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{3y^8}{5y^3} \)
\( \frac{3}{5} \) y(8 - 3)
\(\frac{3}{5}\)y5
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 35% off." If Alex buys two shirts, each with a regular price of $40, how much money will he save?
| $2.00 | |
| $14.00 | |
| $20.00 | |
| $18.00 |
By buying two shirts, Alex will save $40 x \( \frac{35}{100} \) = \( \frac{$40 x 35}{100} \) = \( \frac{$1400}{100} \) = $14.00 on the second shirt.
On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 40% of his shots. If the guard takes 15 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 17 | |
| 13 | |
| 30 | |
| 12 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{40}{100} \) = \( \frac{40 x 15}{100} \) = \( \frac{600}{100} \) = 6 shots
The center makes 35% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{6}{\frac{35}{100}} \) = 6 x \( \frac{100}{35} \) = \( \frac{6 x 100}{35} \) = \( \frac{600}{35} \) = 17 shots
to make the same number of shots as the guard and thus score the same number of points.
A factor is a positive __________ that divides evenly into a given number.
improper fraction |
|
fraction |
|
integer |
|
mixed number |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
16 members of a bridal party need transported to a wedding reception but there are only 4 3-passenger taxis available to take them. How many will need to find other transportation?
| 4 | |
| 1 | |
| 6 | |
| 3 |
There are 4 3-passenger taxis available so that's 4 x 3 = 12 total seats. There are 16 people needing transportation leaving 16 - 12 = 4 who will have to find other transportation.