| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.87 |
| Score | 0% | 57% |
| 7.2 | |
| 0.8 | |
| 0.4 | |
| 1 |
1
If the ratio of home fans to visiting fans in a crowd is 3:1 and all 48,000 seats in a stadium are filled, how many home fans are in attendance?
| 36,800 | |
| 38,400 | |
| 30,750 | |
| 36,000 |
A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:
48,000 fans x \( \frac{3}{4} \) = \( \frac{144000}{4} \) = 36,000 fans.
If all of a roofing company's 10 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 10 | |
| 1 | |
| 6 | |
| 3 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 10 workers at the company now and that's enough to staff 5 crews so there are \( \frac{10}{5} \) = 2 workers on a crew. 8 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 8 x 2 = 16 total workers to staff the crews during the busy season. The company already employs 10 workers so they need to add 16 - 10 = 6 new staff for the busy season.
What is \( \sqrt{\frac{64}{9}} \)?
| 2\(\frac{2}{3}\) | |
| \(\frac{1}{2}\) | |
| \(\frac{5}{9}\) | |
| \(\frac{4}{7}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{64}{9}} \)
\( \frac{\sqrt{64}}{\sqrt{9}} \)
\( \frac{\sqrt{8^2}}{\sqrt{3^2}} \)
\( \frac{8}{3} \)
2\(\frac{2}{3}\)
What is \( \frac{4}{3} \) + \( \frac{9}{9} \)?
| \( \frac{6}{14} \) | |
| 2\(\frac{1}{3}\) | |
| 2 \( \frac{5}{12} \) | |
| \( \frac{7}{15} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 3}{3 x 3} \) + \( \frac{9 x 1}{9 x 1} \)
\( \frac{12}{9} \) + \( \frac{9}{9} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{12 + 9}{9} \) = \( \frac{21}{9} \) = 2\(\frac{1}{3}\)