ASVAB Arithmetic Reasoning Practice Test 240125 Results

Your Results Global Average
Questions 5 5
Correct 0 2.87
Score 0% 57%

Review

1

52% Answer Correctly
7.2
0.8
0.4
1

Solution


1


2

If the ratio of home fans to visiting fans in a crowd is 3:1 and all 48,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
36,800
38,400
30,750
36,000

Solution

A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:

48,000 fans x \( \frac{3}{4} \) = \( \frac{144000}{4} \) = 36,000 fans.


3

If all of a roofing company's 10 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?

55% Answer Correctly
10
1
6
3

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 10 workers at the company now and that's enough to staff 5 crews so there are \( \frac{10}{5} \) = 2 workers on a crew. 8 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 8 x 2 = 16 total workers to staff the crews during the busy season. The company already employs 10 workers so they need to add 16 - 10 = 6 new staff for the busy season.


4

What is \( \sqrt{\frac{64}{9}} \)?

70% Answer Correctly
2\(\frac{2}{3}\)
\(\frac{1}{2}\)
\(\frac{5}{9}\)
\(\frac{4}{7}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{64}{9}} \)
\( \frac{\sqrt{64}}{\sqrt{9}} \)
\( \frac{\sqrt{8^2}}{\sqrt{3^2}} \)
\( \frac{8}{3} \)
2\(\frac{2}{3}\)


5

What is \( \frac{4}{3} \) + \( \frac{9}{9} \)?

59% Answer Correctly
\( \frac{6}{14} \)
2\(\frac{1}{3}\)
2 \( \frac{5}{12} \)
\( \frac{7}{15} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [9, 18, 27, 36, 45] making 9 the smallest multiple 3 and 9 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{4 x 3}{3 x 3} \) + \( \frac{9 x 1}{9 x 1} \)

\( \frac{12}{9} \) + \( \frac{9}{9} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{12 + 9}{9} \) = \( \frac{21}{9} \) = 2\(\frac{1}{3}\)