ASVAB Arithmetic Reasoning Practice Test 244751 Results

Your Results Global Average
Questions 5 5
Correct 0 2.78
Score 0% 56%

Review

1

What is \( 6 \)\( \sqrt{8} \) + \( 6 \)\( \sqrt{2} \)

35% Answer Correctly
12\( \sqrt{8} \)
36\( \sqrt{16} \)
18\( \sqrt{2} \)
36\( \sqrt{4} \)

Solution

To add these radicals together their radicands must be the same:

6\( \sqrt{8} \) + 6\( \sqrt{2} \)
6\( \sqrt{4 \times 2} \) + 6\( \sqrt{2} \)
6\( \sqrt{2^2 \times 2} \) + 6\( \sqrt{2} \)
(6)(2)\( \sqrt{2} \) + 6\( \sqrt{2} \)
12\( \sqrt{2} \) + 6\( \sqrt{2} \)

Now that the radicands are identical, you can add them together:

12\( \sqrt{2} \) + 6\( \sqrt{2} \)
(12 + 6)\( \sqrt{2} \)
18\( \sqrt{2} \)


2

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

59% Answer Correctly

distributive

PEDMAS

commutative

associative


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


3

Which of the following is not a prime number?

64% Answer Correctly

5

2

9

7


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


4

A bread recipe calls for 3\(\frac{3}{8}\) cups of flour. If you only have 1\(\frac{1}{2}\) cups, how much more flour is needed?

62% Answer Correctly
\(\frac{1}{2}\) cups
1\(\frac{7}{8}\) cups
2\(\frac{1}{4}\) cups
1\(\frac{5}{8}\) cups

Solution

The amount of flour you need is (3\(\frac{3}{8}\) - 1\(\frac{1}{2}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{27}{8} \) - \( \frac{12}{8} \)) cups
\( \frac{15}{8} \) cups
1\(\frac{7}{8}\) cups


5

If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?

55% Answer Correctly
9
12
5
16

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 24 - 12 = 12 new staff for the busy season.