ASVAB Arithmetic Reasoning Practice Test 246608 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1

What is 8y7 - 9y7?

71% Answer Correctly
y-7
17y49
-y7
17y-14

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

8y7 - 9y7
(8 - 9)y7
-y7


2

Find the average of the following numbers: 14, 8, 14, 8.

75% Answer Correctly
16
6
10
11

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{14 + 8 + 14 + 8}{4} \) = \( \frac{44}{4} \) = 11


3

What is the least common multiple of 4 and 10?

72% Answer Correctly
32
20
22
21

Solution

The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [20, 40, 60, 80] making 20 the smallest multiple 4 and 10 have in common.


4

a(b + c) = ab + ac defines which of the following?

74% Answer Correctly

distributive property for division

commutative property for multiplication

distributive property for multiplication

commutative property for division


Solution

The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.


5

What is \( 4 \)\( \sqrt{12} \) - \( 4 \)\( \sqrt{3} \)

39% Answer Correctly
16\( \sqrt{12} \)
0\( \sqrt{36} \)
16\( \sqrt{3} \)
4\( \sqrt{3} \)

Solution

To subtract these radicals together their radicands must be the same:

4\( \sqrt{12} \) - 4\( \sqrt{3} \)
4\( \sqrt{4 \times 3} \) - 4\( \sqrt{3} \)
4\( \sqrt{2^2 \times 3} \) - 4\( \sqrt{3} \)
(4)(2)\( \sqrt{3} \) - 4\( \sqrt{3} \)
8\( \sqrt{3} \) - 4\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

8\( \sqrt{3} \) - 4\( \sqrt{3} \)
(8 - 4)\( \sqrt{3} \)
4\( \sqrt{3} \)