ASVAB Arithmetic Reasoning Practice Test 252391 Results

Your Results Global Average
Questions 5 5
Correct 0 2.79
Score 0% 56%

Review

1

What is \( \frac{3}{9} \) x \( \frac{3}{6} \)?

72% Answer Correctly
\(\frac{3}{10}\)
1\(\frac{1}{2}\)
1
\(\frac{1}{6}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{9} \) x \( \frac{3}{6} \) = \( \frac{3 x 3}{9 x 6} \) = \( \frac{9}{54} \) = \(\frac{1}{6}\)


2

Solve 3 + (5 + 3) ÷ 4 x 4 - 42

52% Answer Correctly
\(\frac{2}{3}\)
\(\frac{1}{2}\)
-5
1

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (5 + 3) ÷ 4 x 4 - 42
P: 3 + (8) ÷ 4 x 4 - 42
E: 3 + 8 ÷ 4 x 4 - 16
MD: 3 + \( \frac{8}{4} \) x 4 - 16
MD: 3 + \( \frac{32}{4} \) - 16
AS: \( \frac{12}{4} \) + \( \frac{32}{4} \) - 16
AS: \( \frac{44}{4} \) - 16
AS: \( \frac{44 - 64}{4} \)
\( \frac{-20}{4} \)
-5


3

If all of a roofing company's 12 workers are required to staff 3 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?

55% Answer Correctly
17
19
20
18

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 3 crews so there are \( \frac{12}{3} \) = 4 workers on a crew. 8 crews are needed for the busy season which, at 4 workers per crew, means that the roofing company will need 8 x 4 = 32 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 32 - 12 = 20 new staff for the busy season.


4

Simplify \( \sqrt{125} \)

62% Answer Correctly
3\( \sqrt{10} \)
4\( \sqrt{5} \)
7\( \sqrt{10} \)
5\( \sqrt{5} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{125} \)
\( \sqrt{25 \times 5} \)
\( \sqrt{5^2 \times 5} \)
5\( \sqrt{5} \)


5

What is \( 8 \)\( \sqrt{27} \) + \( 3 \)\( \sqrt{3} \)

35% Answer Correctly
24\( \sqrt{3} \)
11\( \sqrt{81} \)
11\( \sqrt{3} \)
27\( \sqrt{3} \)

Solution

To add these radicals together their radicands must be the same:

8\( \sqrt{27} \) + 3\( \sqrt{3} \)
8\( \sqrt{9 \times 3} \) + 3\( \sqrt{3} \)
8\( \sqrt{3^2 \times 3} \) + 3\( \sqrt{3} \)
(8)(3)\( \sqrt{3} \) + 3\( \sqrt{3} \)
24\( \sqrt{3} \) + 3\( \sqrt{3} \)

Now that the radicands are identical, you can add them together:

24\( \sqrt{3} \) + 3\( \sqrt{3} \)
(24 + 3)\( \sqrt{3} \)
27\( \sqrt{3} \)