| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.40 |
| Score | 0% | 68% |
What is the least common multiple of 3 and 5?
| 15 | |
| 2 | |
| 13 | |
| 1 |
The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50]. The first few multiples they share are [15, 30, 45, 60, 75] making 15 the smallest multiple 3 and 5 have in common.
How many 12-passenger vans will it take to drive all 79 members of the football team to an away game?
| 8 vans | |
| 7 vans | |
| 6 vans | |
| 4 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{79}{12} \) = 6\(\frac{7}{12}\)
So, it will take 6 full vans and one partially full van to transport the entire team making a total of 7 vans.
What is -3c6 + 8c6?
| 5c6 | |
| 11c-6 | |
| 5c12 | |
| 11c6 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-3c6 + 8c6
(-3 + 8)c6
5c6
If the ratio of home fans to visiting fans in a crowd is 2:1 and all 44,000 seats in a stadium are filled, how many home fans are in attendance?
| 25,333 | |
| 40,000 | |
| 29,333 | |
| 29,600 |
A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:
44,000 fans x \( \frac{2}{3} \) = \( \frac{88000}{3} \) = 29,333 fans.
What is the next number in this sequence: 1, 4, 10, 19, 31, __________ ?
| 44 | |
| 49 | |
| 46 | |
| 51 |
The equation for this sequence is:
an = an-1 + 3(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 3(6 - 1)
a6 = 31 + 3(5)
a6 = 46