| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.52 |
| Score | 0% | 70% |
4! = ?
5 x 4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
|
4 x 3 |
|
4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
A triathlon course includes a 100m swim, a 40.6km bike ride, and a 5.300000000000001km run. What is the total length of the race course?
| 27.4km | |
| 59.1km | |
| 46km | |
| 55.4km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 40.6km + 5.300000000000001km
total distance = 46km
| 2.4 | |
| 0.6 | |
| 1.2 | |
| 1 |
1
What is \( \frac{8}{3} \) + \( \frac{6}{11} \)?
| \( \frac{3}{33} \) | |
| 3\(\frac{7}{33}\) | |
| 2 \( \frac{3}{9} \) | |
| 2 \( \frac{4}{11} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{8 x 11}{3 x 11} \) + \( \frac{6 x 3}{11 x 3} \)
\( \frac{88}{33} \) + \( \frac{18}{33} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{88 + 18}{33} \) = \( \frac{106}{33} \) = 3\(\frac{7}{33}\)
What is the distance in miles of a trip that takes 2 hours at an average speed of 55 miles per hour?
| 150 miles | |
| 240 miles | |
| 105 miles | |
| 110 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 55mph \times 2h \)
110 miles