| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
If \( \left|b + 7\right| \) + 8 = 5, which of these is a possible value for b?
| -4 | |
| 12 | |
| 4 | |
| -14 |
First, solve for \( \left|b + 7\right| \):
\( \left|b + 7\right| \) + 8 = 5
\( \left|b + 7\right| \) = 5 - 8
\( \left|b + 7\right| \) = -3
The value inside the absolute value brackets can be either positive or negative so (b + 7) must equal - 3 or --3 for \( \left|b + 7\right| \) to equal -3:
| b + 7 = -3 b = -3 - 7 b = -10 | b + 7 = 3 b = 3 - 7 b = -4 |
So, b = -4 or b = -10.
What is \( \sqrt{\frac{81}{9}} \)?
| 3 | |
| \(\frac{1}{2}\) | |
| \(\frac{1}{3}\) | |
| \(\frac{6}{7}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{81}{9}} \)
\( \frac{\sqrt{81}}{\sqrt{9}} \)
\( \frac{\sqrt{9^2}}{\sqrt{3^2}} \)
\( \frac{9}{3} \)
3
A bread recipe calls for 2\(\frac{7}{8}\) cups of flour. If you only have \(\frac{5}{8}\) cup, how much more flour is needed?
| 1\(\frac{3}{8}\) cups | |
| 1\(\frac{1}{2}\) cups | |
| 2\(\frac{7}{8}\) cups | |
| 2\(\frac{1}{4}\) cups |
The amount of flour you need is (2\(\frac{7}{8}\) - \(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{23}{8} \) - \( \frac{5}{8} \)) cups
\( \frac{18}{8} \) cups
2\(\frac{1}{4}\) cups
Which of these numbers is a factor of 20?
| 3 | |
| 5 | |
| 15 | |
| 6 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 20 are 1, 2, 4, 5, 10, 20.
If there were a total of 100 raffle tickets sold and you bought 2 tickets, what's the probability that you'll win the raffle?
| 16% | |
| 2% | |
| 15% | |
| 14% |
You have 2 out of the total of 100 raffle tickets sold so you have a (\( \frac{2}{100} \)) x 100 = \( \frac{2 \times 100}{100} \) = \( \frac{200}{100} \) = 2% chance to win the raffle.