| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.19 |
| Score | 0% | 64% |
If all of a roofing company's 6 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 4 complete crews out on jobs?
| 6 | |
| 17 | |
| 18 | |
| 10 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 2 crews so there are \( \frac{6}{2} \) = 3 workers on a crew. 4 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 4 x 3 = 12 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 12 - 6 = 6 new staff for the busy season.
A factor is a positive __________ that divides evenly into a given number.
mixed number |
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integer |
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fraction |
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improper fraction |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
A bread recipe calls for 2\(\frac{3}{4}\) cups of flour. If you only have 1\(\frac{1}{4}\) cups, how much more flour is needed?
| 2\(\frac{3}{8}\) cups | |
| 1\(\frac{1}{2}\) cups | |
| 2\(\frac{1}{8}\) cups | |
| 1\(\frac{3}{8}\) cups |
The amount of flour you need is (2\(\frac{3}{4}\) - 1\(\frac{1}{4}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{22}{8} \) - \( \frac{10}{8} \)) cups
\( \frac{12}{8} \) cups
1\(\frac{1}{2}\) cups
Find the average of the following numbers: 17, 9, 17, 9.
| 11 | |
| 13 | |
| 17 | |
| 9 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{17 + 9 + 17 + 9}{4} \) = \( \frac{52}{4} \) = 13
If a rectangle is twice as long as it is wide and has a perimeter of 18 meters, what is the area of the rectangle?
| 50 m2 | |
| 162 m2 | |
| 8 m2 | |
| 18 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 18 meters so the equation becomes: 2w + 2h = 18.
Putting these two equations together and solving for width (w):
2w + 2h = 18
w + h = \( \frac{18}{2} \)
w + h = 9
w = 9 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 9 - 2w
3w = 9
w = \( \frac{9}{3} \)
w = 3
Since h = 2w that makes h = (2 x 3) = 6 and the area = h x w = 3 x 6 = 18 m2