| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.74 |
| Score | 0% | 55% |
Which of the following statements about exponents is false?
b1 = b |
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all of these are false |
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b0 = 1 |
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b1 = 1 |
A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).
What is \( 8 \)\( \sqrt{18} \) - \( 9 \)\( \sqrt{2} \)
| -1\( \sqrt{2} \) | |
| 72\( \sqrt{9} \) | |
| -1\( \sqrt{36} \) | |
| 15\( \sqrt{2} \) |
To subtract these radicals together their radicands must be the same:
8\( \sqrt{18} \) - 9\( \sqrt{2} \)
8\( \sqrt{9 \times 2} \) - 9\( \sqrt{2} \)
8\( \sqrt{3^2 \times 2} \) - 9\( \sqrt{2} \)
(8)(3)\( \sqrt{2} \) - 9\( \sqrt{2} \)
24\( \sqrt{2} \) - 9\( \sqrt{2} \)
Now that the radicands are identical, you can subtract them:
24\( \sqrt{2} \) - 9\( \sqrt{2} \)A tiger in a zoo has consumed 40 pounds of food in 4 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 90 pounds?
| 7 | |
| 5 | |
| 3 | |
| 9 |
If the tiger has consumed 40 pounds of food in 4 days that's \( \frac{40}{4} \) = 10 pounds of food per day. The tiger needs to consume 90 - 40 = 50 more pounds of food to reach 90 pounds total. At 10 pounds of food per day that's \( \frac{50}{10} \) = 5 more days.
What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?
| 33 | |
| 28 | |
| 29 | |
| 31 |
The equation for this sequence is:
an = an-1 + 2(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 2(6 - 1)
a6 = 21 + 2(5)
a6 = 31
What is 7a3 + 8a3?
| 15a3 | |
| a-3 | |
| 15a9 | |
| -a-3 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
7a3 + 8a3
(7 + 8)a3
15a3