| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 50% off." If Ezra buys two shirts, each with a regular price of $18, how much will he pay for both shirts?
| $9.00 | |
| $27.00 | |
| 7 | |
| $20.70 |
By buying two shirts, Ezra will save $18 x \( \frac{50}{100} \) = \( \frac{$18 x 50}{100} \) = \( \frac{$900}{100} \) = $9.00 on the second shirt.
So, his total cost will be
$18.00 + ($18.00 - $9.00)
$18.00 + $9.00
$27.00
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Ezra buys two shirts, each with a regular price of $20, how much money will he save?
| $10.00 | |
| $1.00 | |
| $2.00 | |
| $5.00 |
By buying two shirts, Ezra will save $20 x \( \frac{5}{100} \) = \( \frac{$20 x 5}{100} \) = \( \frac{$100}{100} \) = $1.00 on the second shirt.
Cooks are needed to prepare for a large party. Each cook can bake either 5 large cakes or 14 small cakes per hour. The kitchen is available for 4 hours and 35 large cakes and 260 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 7 | |
| 12 | |
| 5 | |
| 8 |
If a single cook can bake 5 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 5 x 4 = 20 large cakes during that time. 35 large cakes are needed for the party so \( \frac{35}{20} \) = 1\(\frac{3}{4}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 14 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 14 x 4 = 56 small cakes during that time. 260 small cakes are needed for the party so \( \frac{260}{56} \) = 4\(\frac{9}{14}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 2 + 5 = 7 cooks.
Which of the following is a mixed number?
\({7 \over 5} \) |
|
\({5 \over 7} \) |
|
\({a \over 5} \) |
|
\(1 {2 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is \( \frac{5}{3} \) + \( \frac{8}{11} \)?
| \( \frac{5}{33} \) | |
| 2\(\frac{13}{33}\) | |
| 1 \( \frac{7}{16} \) | |
| 2 \( \frac{1}{33} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 11 are [11, 22, 33, 44, 55, 66, 77, 88, 99]. The first few multiples they share are [33, 66, 99] making 33 the smallest multiple 3 and 11 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{5 x 11}{3 x 11} \) + \( \frac{8 x 3}{11 x 3} \)
\( \frac{55}{33} \) + \( \frac{24}{33} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{55 + 24}{33} \) = \( \frac{79}{33} \) = 2\(\frac{13}{33}\)