| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
What is \( \frac{3}{7} \) ÷ \( \frac{1}{5} \)?
| \(\frac{3}{40}\) | |
| 15 | |
| \(\frac{1}{8}\) | |
| 2\(\frac{1}{7}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{3}{7} \) ÷ \( \frac{1}{5} \) = \( \frac{3}{7} \) x \( \frac{5}{1} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{7} \) x \( \frac{5}{1} \) = \( \frac{3 x 5}{7 x 1} \) = \( \frac{15}{7} \) = 2\(\frac{1}{7}\)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 15% off." If Charlie buys two shirts, each with a regular price of $40, how much will he pay for both shirts?
| $56.00 | |
| $34.00 | |
| $74.00 | |
| $60.00 |
By buying two shirts, Charlie will save $40 x \( \frac{15}{100} \) = \( \frac{$40 x 15}{100} \) = \( \frac{$600}{100} \) = $6.00 on the second shirt.
So, his total cost will be
$40.00 + ($40.00 - $6.00)
$40.00 + $34.00
$74.00
Solve for \( \frac{4!}{6!} \)
| \( \frac{1}{30} \) | |
| 120 | |
| \( \frac{1}{8} \) | |
| \( \frac{1}{20} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{6!} \)
\( \frac{4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5} \)
\( \frac{1}{30} \)
A triathlon course includes a 100m swim, a 30.3km bike ride, and a 6.4km run. What is the total length of the race course?
| 46.4km | |
| 41.2km | |
| 67.3km | |
| 36.8km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.1km + 30.3km + 6.4km
total distance = 36.8km
In a class of 21 students, 5 are taking German and 5 are taking Spanish. Of the students studying German or Spanish, 2 are taking both courses. How many students are not enrolled in either course?
| 13 | |
| 11 | |
| 15 | |
| 16 |
The number of students taking German or Spanish is 5 + 5 = 10. Of that group of 10, 2 are taking both languages so they've been counted twice (once in the German group and once in the Spanish group). Subtracting them out leaves 10 - 2 = 8 who are taking at least one language. 21 - 8 = 13 students who are not taking either language.