ASVAB Arithmetic Reasoning Practice Test 264160 Results

Your Results Global Average
Questions 5 5
Correct 0 3.02
Score 0% 60%

Review

1

How many 2 gallon cans worth of fuel would you need to pour into an empty 16 gallon tank to fill it exactly halfway?

52% Answer Correctly
9
4
8
2

Solution

To fill a 16 gallon tank exactly halfway you'll need 8 gallons of fuel. Each fuel can holds 2 gallons so:

cans = \( \frac{8 \text{ gallons}}{2 \text{ gallons}} \) = 4


2

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common multiple

least common multiple

absolute value

greatest common factor


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.


3

What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?

69% Answer Correctly
53
57
62
61

Solution

The equation for this sequence is:

an = an-1 + 4(n - 1)

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61


4

What is 9\( \sqrt{7} \) x 5\( \sqrt{4} \)?

41% Answer Correctly
45\( \sqrt{7} \)
90\( \sqrt{7} \)
14\( \sqrt{28} \)
45\( \sqrt{4} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

9\( \sqrt{7} \) x 5\( \sqrt{4} \)
(9 x 5)\( \sqrt{7 \times 4} \)
45\( \sqrt{28} \)

Now we need to simplify the radical:

45\( \sqrt{28} \)
45\( \sqrt{7 \times 4} \)
45\( \sqrt{7 \times 2^2} \)
(45)(2)\( \sqrt{7} \)
90\( \sqrt{7} \)


5

What is the least common multiple of 6 and 12?

72% Answer Correctly
5
17
6
12

Solution

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 6 and 12 have in common.