There are 3 5-passenger taxis available so that's 3 x 5 = 15 total seats. There are 17 people needing transportation leaving 17 - 15 = 2 who will have to find other transportation.

First, solve for \( \left|c + 0\right| \):

\( \left|c + 0\right| \) - 6 = -1
\( \left|c + 0\right| \) = -1 + 6
\( \left|c + 0\right| \) = 5

The value inside the absolute value brackets can be either positive or negative so (c + 0) must equal + 5 or -5 for \( \left|c + 0\right| \) to equal 5:

So, c = -5 or c = 5.

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{6!}{3!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{6 \times 5 \times 4}{1} \)
\( 6 \times 5 \times 4 \)
120

The equation for this sequence is:

a_n = a_n-1 + 2(n - 1)

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 2(6 - 1)
a₆ = 21 + 2(5)
a₆ = 31

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{7} \) x \( \frac{3}{9} \) = \( \frac{3 x 3}{7 x 9} \) = \( \frac{9}{63} \) = \(\frac{1}{7}\)