| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.97 |
| Score | 0% | 59% |
If a mayor is elected with 80% of the votes cast and 64% of a town's 29,000 voters cast a vote, how many votes did the mayor receive?
| 12,435 | |
| 14,848 | |
| 14,291 | |
| 11,136 |
If 64% of the town's 29,000 voters cast ballots the number of votes cast is:
(\( \frac{64}{100} \)) x 29,000 = \( \frac{1,856,000}{100} \) = 18,560
The mayor got 80% of the votes cast which is:
(\( \frac{80}{100} \)) x 18,560 = \( \frac{1,484,800}{100} \) = 14,848 votes.
Solve for \( \frac{6!}{2!} \)
| \( \frac{1}{60480} \) | |
| \( \frac{1}{42} \) | |
| 360 | |
| 56 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{6!}{2!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{6 \times 5 \times 4 \times 3}{1} \)
\( 6 \times 5 \times 4 \times 3 \)
360
If there were a total of 200 raffle tickets sold and you bought 6 tickets, what's the probability that you'll win the raffle?
| 8% | |
| 17% | |
| 3% | |
| 9% |
You have 6 out of the total of 200 raffle tickets sold so you have a (\( \frac{6}{200} \)) x 100 = \( \frac{6 \times 100}{200} \) = \( \frac{600}{200} \) = 3% chance to win the raffle.
If \(\left|a\right| = 7\), which of the following best describes a?
a = -7 |
|
a = 7 |
|
a = 7 or a = -7 |
|
none of these is correct |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
Solve 5 + (4 + 4) ÷ 5 x 2 - 22
| 1\(\frac{3}{5}\) | |
| 4\(\frac{1}{5}\) | |
| 3 | |
| 1 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (4 + 4) ÷ 5 x 2 - 22
P: 5 + (8) ÷ 5 x 2 - 22
E: 5 + 8 ÷ 5 x 2 - 4
MD: 5 + \( \frac{8}{5} \) x 2 - 4
MD: 5 + \( \frac{16}{5} \) - 4
AS: \( \frac{25}{5} \) + \( \frac{16}{5} \) - 4
AS: \( \frac{41}{5} \) - 4
AS: \( \frac{41 - 20}{5} \)
\( \frac{21}{5} \)
4\(\frac{1}{5}\)