ASVAB Arithmetic Reasoning Practice Test 267939 Results

Your Results Global Average
Questions 5 5
Correct 0 3.29
Score 0% 66%

Review

1

Which of the following is an improper fraction?

70% Answer Correctly

\({a \over 5} \)

\(1 {2 \over 5} \)

\({2 \over 5} \)

\({7 \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


2

Simplify \( \frac{28}{60} \).

77% Answer Correctly
\( \frac{7}{15} \)
\( \frac{6}{19} \)
\( \frac{6}{17} \)
\( \frac{9}{19} \)

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 28 are [1, 2, 4, 7, 14, 28] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{28}{60} \) = \( \frac{\frac{28}{4}}{\frac{60}{4}} \) = \( \frac{7}{15} \)


3

A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?

51% Answer Correctly
30%
15%
32\(\frac{1}{2}\)%
35%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%


4

What is \( \frac{-9a^8}{9a^3} \)?

60% Answer Correctly
-a\(\frac{3}{8}\)
-a11
-a2\(\frac{2}{3}\)
-a5

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-9a^8}{9a^3} \)
\( \frac{-9}{9} \) a(8 - 3)
-a5


5

Convert z-2 to remove the negative exponent.

68% Answer Correctly
\( \frac{1}{z^2} \)
\( \frac{-1}{z^{-2}} \)
\( \frac{2}{z} \)
\( \frac{1}{z^{-2}} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.