If the tiger has consumed 42 pounds of food in 7 days that's \( \frac{42}{7} \) = 6 pounds of food per day. The tiger needs to consume 84 - 42 = 42 more pounds of food to reach 84 pounds total. At 6 pounds of food per day that's \( \frac{42}{6} \) = 7 more days.

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{12 + 8 + 12 + 8}{4} \) = \( \frac{40}{4} \) = 10

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{35\sqrt{21}}{7\sqrt{3}} \)
\( \frac{35}{7} \) \( \sqrt{\frac{21}{3}} \)
5 \( \sqrt{7} \)

To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 48 are [1, 2, 3, 4, 6, 8, 12, 16, 24, 48]. They share 3 factors [1, 2, 4] making 4 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

\( \frac{20}{48} \) = \( \frac{\frac{20}{4}}{\frac{48}{4}} \) = \( \frac{5}{12} \)

You have 12 out of the total of 200 raffle tickets sold so you have a (\( \frac{12}{200} \)) x 100 = \( \frac{12 \times 100}{200} \) = \( \frac{1200}{200} \) = 6% chance to win the raffle.