| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.29 |
| Score | 0% | 66% |
If a rectangle is twice as long as it is wide and has a perimeter of 48 meters, what is the area of the rectangle?
| 32 m2 | |
| 8 m2 | |
| 128 m2 | |
| 72 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 48 meters so the equation becomes: 2w + 2h = 48.
Putting these two equations together and solving for width (w):
2w + 2h = 48
w + h = \( \frac{48}{2} \)
w + h = 24
w = 24 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 24 - 2w
3w = 24
w = \( \frac{24}{3} \)
w = 8
Since h = 2w that makes h = (2 x 8) = 16 and the area = h x w = 8 x 16 = 128 m2
How many 15-passenger vans will it take to drive all 49 members of the football team to an away game?
| 14 vans | |
| 6 vans | |
| 4 vans | |
| 9 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{49}{15} \) = 3\(\frac{4}{15}\)
So, it will take 3 full vans and one partially full van to transport the entire team making a total of 4 vans.
Simplify \( \sqrt{175} \)
| 8\( \sqrt{14} \) | |
| 5\( \sqrt{7} \) | |
| 3\( \sqrt{7} \) | |
| 6\( \sqrt{14} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{175} \)
\( \sqrt{25 \times 7} \)
\( \sqrt{5^2 \times 7} \)
5\( \sqrt{7} \)
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Ezra buys two shirts, each with a regular price of $14, how much money will he save?
| $2.80 | |
| $4.20 | |
| $4.90 | |
| $6.30 |
By buying two shirts, Ezra will save $14 x \( \frac{30}{100} \) = \( \frac{$14 x 30}{100} \) = \( \frac{$420}{100} \) = $4.20 on the second shirt.
What is the next number in this sequence: 1, 5, 13, 25, 41, __________ ?
| 61 | |
| 56 | |
| 64 | |
| 70 |
The equation for this sequence is:
an = an-1 + 4(n - 1)
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 4(6 - 1)
a6 = 41 + 4(5)
a6 = 61