Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

5 + (3 + 3) ÷ 2 x 4 - 2²
P: 5 + (6) ÷ 2 x 4 - 2²
E: 5 + 6 ÷ 2 x 4 - 4
MD: 5 + \( \frac{6}{2} \) x 4 - 4
MD: 5 + \( \frac{24}{2} \) - 4
AS: \( \frac{10}{2} \) + \( \frac{24}{2} \) - 4
AS: \( \frac{34}{2} \) - 4
AS: \( \frac{34 - 8}{2} \)
\( \frac{26}{2} \)
13

The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 have in common.

To fill a 12 gallon tank exactly halfway you'll need 6 gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:

cans = \( \frac{6 \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 4

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.

To subtract these radicals together their radicands must be the same:

6\( \sqrt{75} \) - 8\( \sqrt{3} \)
6\( \sqrt{25 \times 3} \) - 8\( \sqrt{3} \)
6\( \sqrt{5^2 \times 3} \) - 8\( \sqrt{3} \)
(6)(5)\( \sqrt{3} \) - 8\( \sqrt{3} \)
30\( \sqrt{3} \) - 8\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them: