ASVAB Arithmetic Reasoning Practice Test 275404 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1

What is -6y6 + 2y6?

66% Answer Correctly
-4y6
-4y12
-4y-12
-8y6

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

-6y6 + 2y6
(-6 + 2)y6
-4y6


2

What is \( 2 \)\( \sqrt{20} \) + \( 9 \)\( \sqrt{5} \)

35% Answer Correctly
18\( \sqrt{4} \)
11\( \sqrt{5} \)
13\( \sqrt{5} \)
18\( \sqrt{5} \)

Solution

To add these radicals together their radicands must be the same:

2\( \sqrt{20} \) + 9\( \sqrt{5} \)
2\( \sqrt{4 \times 5} \) + 9\( \sqrt{5} \)
2\( \sqrt{2^2 \times 5} \) + 9\( \sqrt{5} \)
(2)(2)\( \sqrt{5} \) + 9\( \sqrt{5} \)
4\( \sqrt{5} \) + 9\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

4\( \sqrt{5} \) + 9\( \sqrt{5} \)
(4 + 9)\( \sqrt{5} \)
13\( \sqrt{5} \)


3

A bread recipe calls for 3\(\frac{1}{4}\) cups of flour. If you only have 1\(\frac{5}{8}\) cups, how much more flour is needed?

62% Answer Correctly
\(\frac{7}{8}\) cups
1\(\frac{5}{8}\) cups
2\(\frac{1}{8}\) cups
\(\frac{1}{2}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{4}\) - 1\(\frac{5}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{26}{8} \) - \( \frac{13}{8} \)) cups
\( \frac{13}{8} \) cups
1\(\frac{5}{8}\) cups


4

The total water usage for a city is 45,000 gallons each day. Of that total, 16% is for personal use and 47% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?

58% Answer Correctly
13,950
3,900
2,100
1,800

Solution

47% of the water consumption is industrial use and 16% is personal use so (47% - 16%) = 31% more water is used for industrial purposes. 45,000 gallons are consumed daily so industry consumes \( \frac{31}{100} \) x 45,000 gallons = 13,950 gallons.


5

What is 6c3 - 7c3?

71% Answer Correctly
c3
-c-3
-c3
c-3

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

6c3 - 7c3
(6 - 7)c3
-c3