ASVAB Arithmetic Reasoning Practice Test 275463 Results

Your Results Global Average
Questions 5 5
Correct 0 2.57
Score 0% 51%

Review

1

If a mayor is elected with 59% of the votes cast and 68% of a town's 11,000 voters cast a vote, how many votes did the mayor receive?

49% Answer Correctly
4,413
4,264
5,386
3,890

Solution

If 68% of the town's 11,000 voters cast ballots the number of votes cast is:

(\( \frac{68}{100} \)) x 11,000 = \( \frac{748,000}{100} \) = 7,480

The mayor got 59% of the votes cast which is:

(\( \frac{59}{100} \)) x 7,480 = \( \frac{441,320}{100} \) = 4,413 votes.


2

What is \( 2 \)\( \sqrt{28} \) - \( 9 \)\( \sqrt{7} \)

38% Answer Correctly
18\( \sqrt{7} \)
18\( \sqrt{196} \)
-5\( \sqrt{7} \)
-7\( \sqrt{28} \)

Solution

To subtract these radicals together their radicands must be the same:

2\( \sqrt{28} \) - 9\( \sqrt{7} \)
2\( \sqrt{4 \times 7} \) - 9\( \sqrt{7} \)
2\( \sqrt{2^2 \times 7} \) - 9\( \sqrt{7} \)
(2)(2)\( \sqrt{7} \) - 9\( \sqrt{7} \)
4\( \sqrt{7} \) - 9\( \sqrt{7} \)

Now that the radicands are identical, you can subtract them:

4\( \sqrt{7} \) - 9\( \sqrt{7} \)
(4 - 9)\( \sqrt{7} \)
-5\( \sqrt{7} \)


3

Which of the following is an improper fraction?

70% Answer Correctly

\({2 \over 5} \)

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


4

On average, the center for a basketball team hits 25% of his shots while a guard on the same team hits 30% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?

42% Answer Correctly
12
11
14
24

Solution
If the guard hits 30% of his shots and takes 20 shots he'll make:

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{30}{100} \) = \( \frac{30 x 20}{100} \) = \( \frac{600}{100} \) = 6 shots

The center makes 25% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{6}{\frac{25}{100}} \) = 6 x \( \frac{100}{25} \) = \( \frac{6 x 100}{25} \) = \( \frac{600}{25} \) = 24 shots

to make the same number of shots as the guard and thus score the same number of points.


5

Solve 5 + (5 + 4) ÷ 2 x 2 - 52

52% Answer Correctly
\(\frac{7}{9}\)
2\(\frac{1}{4}\)
2\(\frac{1}{3}\)
-11

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

5 + (5 + 4) ÷ 2 x 2 - 52
P: 5 + (9) ÷ 2 x 2 - 52
E: 5 + 9 ÷ 2 x 2 - 25
MD: 5 + \( \frac{9}{2} \) x 2 - 25
MD: 5 + \( \frac{18}{2} \) - 25
AS: \( \frac{10}{2} \) + \( \frac{18}{2} \) - 25
AS: \( \frac{28}{2} \) - 25
AS: \( \frac{28 - 50}{2} \)
\( \frac{-22}{2} \)
-11