| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.57 |
| Score | 0% | 51% |
If a mayor is elected with 59% of the votes cast and 68% of a town's 11,000 voters cast a vote, how many votes did the mayor receive?
| 4,413 | |
| 4,264 | |
| 5,386 | |
| 3,890 |
If 68% of the town's 11,000 voters cast ballots the number of votes cast is:
(\( \frac{68}{100} \)) x 11,000 = \( \frac{748,000}{100} \) = 7,480
The mayor got 59% of the votes cast which is:
(\( \frac{59}{100} \)) x 7,480 = \( \frac{441,320}{100} \) = 4,413 votes.
What is \( 2 \)\( \sqrt{28} \) - \( 9 \)\( \sqrt{7} \)
| 18\( \sqrt{7} \) | |
| 18\( \sqrt{196} \) | |
| -5\( \sqrt{7} \) | |
| -7\( \sqrt{28} \) |
To subtract these radicals together their radicands must be the same:
2\( \sqrt{28} \) - 9\( \sqrt{7} \)
2\( \sqrt{4 \times 7} \) - 9\( \sqrt{7} \)
2\( \sqrt{2^2 \times 7} \) - 9\( \sqrt{7} \)
(2)(2)\( \sqrt{7} \) - 9\( \sqrt{7} \)
4\( \sqrt{7} \) - 9\( \sqrt{7} \)
Now that the radicands are identical, you can subtract them:
4\( \sqrt{7} \) - 9\( \sqrt{7} \)Which of the following is an improper fraction?
\({2 \over 5} \) |
|
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
|
\({a \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
On average, the center for a basketball team hits 25% of his shots while a guard on the same team hits 30% of his shots. If the guard takes 20 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 12 | |
| 11 | |
| 14 | |
| 24 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 20 x \( \frac{30}{100} \) = \( \frac{30 x 20}{100} \) = \( \frac{600}{100} \) = 6 shots
The center makes 25% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{6}{\frac{25}{100}} \) = 6 x \( \frac{100}{25} \) = \( \frac{6 x 100}{25} \) = \( \frac{600}{25} \) = 24 shots
to make the same number of shots as the guard and thus score the same number of points.
Solve 5 + (5 + 4) ÷ 2 x 2 - 52
| \(\frac{7}{9}\) | |
| 2\(\frac{1}{4}\) | |
| 2\(\frac{1}{3}\) | |
| -11 |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (5 + 4) ÷ 2 x 2 - 52
P: 5 + (9) ÷ 2 x 2 - 52
E: 5 + 9 ÷ 2 x 2 - 25
MD: 5 + \( \frac{9}{2} \) x 2 - 25
MD: 5 + \( \frac{18}{2} \) - 25
AS: \( \frac{10}{2} \) + \( \frac{18}{2} \) - 25
AS: \( \frac{28}{2} \) - 25
AS: \( \frac{28 - 50}{2} \)
\( \frac{-22}{2} \)
-11