ASVAB Arithmetic Reasoning Practice Test 27590 Results

Your Results Global Average
Questions 5 5
Correct 0 2.81
Score 0% 56%

Review

1

What is \( \frac{56\sqrt{56}}{8\sqrt{8}} \)?

71% Answer Correctly
\(\frac{1}{7}\) \( \sqrt{7} \)
7 \( \sqrt{7} \)
7 \( \sqrt{\frac{1}{7}} \)
\(\frac{1}{7}\) \( \sqrt{\frac{1}{7}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{56\sqrt{56}}{8\sqrt{8}} \)
\( \frac{56}{8} \) \( \sqrt{\frac{56}{8}} \)
7 \( \sqrt{7} \)


2

Monica scored 81% on her final exam. If each question was worth 4 points and there were 280 possible points on the exam, how many questions did Monica answer correctly?

57% Answer Correctly
43
57
42
63

Solution

Monica scored 81% on the test meaning she earned 81% of the possible points on the test. There were 280 possible points on the test so she earned 280 x 0.81 = 228 points. Each question is worth 4 points so she got \( \frac{228}{4} \) = 57 questions right.


3

What is \( \frac{4}{8} \) x \( \frac{4}{5} \)?

72% Answer Correctly
\(\frac{1}{8}\)
\(\frac{2}{5}\)
2
3\(\frac{1}{5}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{4}{8} \) x \( \frac{4}{5} \) = \( \frac{4 x 4}{8 x 5} \) = \( \frac{16}{40} \) = \(\frac{2}{5}\)


4

What is 7\( \sqrt{3} \) x 6\( \sqrt{3} \)?

41% Answer Correctly
42\( \sqrt{6} \)
126
42\( \sqrt{3} \)
13\( \sqrt{9} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

7\( \sqrt{3} \) x 6\( \sqrt{3} \)
(7 x 6)\( \sqrt{3 \times 3} \)
42\( \sqrt{9} \)

Now we need to simplify the radical:

42\( \sqrt{9} \)
42\( \sqrt{3^2} \)
(42)(3)
126


5

What is \( 8 \)\( \sqrt{12} \) - \( 5 \)\( \sqrt{3} \)

38% Answer Correctly
3\( \sqrt{12} \)
40\( \sqrt{3} \)
11\( \sqrt{3} \)
3\( \sqrt{4} \)

Solution

To subtract these radicals together their radicands must be the same:

8\( \sqrt{12} \) - 5\( \sqrt{3} \)
8\( \sqrt{4 \times 3} \) - 5\( \sqrt{3} \)
8\( \sqrt{2^2 \times 3} \) - 5\( \sqrt{3} \)
(8)(2)\( \sqrt{3} \) - 5\( \sqrt{3} \)
16\( \sqrt{3} \) - 5\( \sqrt{3} \)

Now that the radicands are identical, you can subtract them:

16\( \sqrt{3} \) - 5\( \sqrt{3} \)
(16 - 5)\( \sqrt{3} \)
11\( \sqrt{3} \)