| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.81 |
| Score | 0% | 56% |
What is \( \frac{56\sqrt{56}}{8\sqrt{8}} \)?
| \(\frac{1}{7}\) \( \sqrt{7} \) | |
| 7 \( \sqrt{7} \) | |
| 7 \( \sqrt{\frac{1}{7}} \) | |
| \(\frac{1}{7}\) \( \sqrt{\frac{1}{7}} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{56\sqrt{56}}{8\sqrt{8}} \)
\( \frac{56}{8} \) \( \sqrt{\frac{56}{8}} \)
7 \( \sqrt{7} \)
Monica scored 81% on her final exam. If each question was worth 4 points and there were 280 possible points on the exam, how many questions did Monica answer correctly?
| 43 | |
| 57 | |
| 42 | |
| 63 |
Monica scored 81% on the test meaning she earned 81% of the possible points on the test. There were 280 possible points on the test so she earned 280 x 0.81 = 228 points. Each question is worth 4 points so she got \( \frac{228}{4} \) = 57 questions right.
What is \( \frac{4}{8} \) x \( \frac{4}{5} \)?
| \(\frac{1}{8}\) | |
| \(\frac{2}{5}\) | |
| 2 | |
| 3\(\frac{1}{5}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{8} \) x \( \frac{4}{5} \) = \( \frac{4 x 4}{8 x 5} \) = \( \frac{16}{40} \) = \(\frac{2}{5}\)
What is 7\( \sqrt{3} \) x 6\( \sqrt{3} \)?
| 42\( \sqrt{6} \) | |
| 126 | |
| 42\( \sqrt{3} \) | |
| 13\( \sqrt{9} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
7\( \sqrt{3} \) x 6\( \sqrt{3} \)
(7 x 6)\( \sqrt{3 \times 3} \)
42\( \sqrt{9} \)
Now we need to simplify the radical:
42\( \sqrt{9} \)
42\( \sqrt{3^2} \)
(42)(3)
126
What is \( 8 \)\( \sqrt{12} \) - \( 5 \)\( \sqrt{3} \)
| 3\( \sqrt{12} \) | |
| 40\( \sqrt{3} \) | |
| 11\( \sqrt{3} \) | |
| 3\( \sqrt{4} \) |
To subtract these radicals together their radicands must be the same:
8\( \sqrt{12} \) - 5\( \sqrt{3} \)
8\( \sqrt{4 \times 3} \) - 5\( \sqrt{3} \)
8\( \sqrt{2^2 \times 3} \) - 5\( \sqrt{3} \)
(8)(2)\( \sqrt{3} \) - 5\( \sqrt{3} \)
16\( \sqrt{3} \) - 5\( \sqrt{3} \)
Now that the radicands are identical, you can subtract them:
16\( \sqrt{3} \) - 5\( \sqrt{3} \)