| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
What is \( \frac{3}{9} \) x \( \frac{1}{5} \)?
| \(\frac{4}{21}\) | |
| \(\frac{1}{3}\) | |
| \(\frac{1}{15}\) | |
| \(\frac{1}{9}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{9} \) x \( \frac{1}{5} \) = \( \frac{3 x 1}{9 x 5} \) = \( \frac{3}{45} \) = \(\frac{1}{15}\)
Find the average of the following numbers: 11, 5, 9, 7.
| 11 | |
| 3 | |
| 8 | |
| 4 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{11 + 5 + 9 + 7}{4} \) = \( \frac{32}{4} \) = 8
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 16 small cakes per hour. The kitchen is available for 4 hours and 36 large cakes and 100 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 6 | |
| 7 | |
| 5 | |
| 11 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 4 hours, a single cook can bake 2 x 4 = 8 large cakes during that time. 36 large cakes are needed for the party so \( \frac{36}{8} \) = 4\(\frac{1}{2}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 16 small cakes per hour and the kitchen is available for 4 hours, a single cook can bake 16 x 4 = 64 small cakes during that time. 100 small cakes are needed for the party so \( \frac{100}{64} \) = 1\(\frac{9}{16}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 5 + 2 = 7 cooks.
What is \( 3 \)\( \sqrt{28} \) + \( 4 \)\( \sqrt{7} \)
| 12\( \sqrt{4} \) | |
| 12\( \sqrt{7} \) | |
| 7\( \sqrt{28} \) | |
| 10\( \sqrt{7} \) |
To add these radicals together their radicands must be the same:
3\( \sqrt{28} \) + 4\( \sqrt{7} \)
3\( \sqrt{4 \times 7} \) + 4\( \sqrt{7} \)
3\( \sqrt{2^2 \times 7} \) + 4\( \sqrt{7} \)
(3)(2)\( \sqrt{7} \) + 4\( \sqrt{7} \)
6\( \sqrt{7} \) + 4\( \sqrt{7} \)
Now that the radicands are identical, you can add them together:
6\( \sqrt{7} \) + 4\( \sqrt{7} \)What is \( \sqrt{\frac{64}{16}} \)?
| 2 | |
| \(\frac{1}{3}\) | |
| \(\frac{4}{7}\) | |
| 3 |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{64}{16}} \)
\( \frac{\sqrt{64}}{\sqrt{16}} \)
\( \frac{\sqrt{8^2}}{\sqrt{4^2}} \)
\( \frac{8}{4} \)
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