| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
If a rectangle is twice as long as it is wide and has a perimeter of 24 meters, what is the area of the rectangle?
| 32 m2 | |
| 2 m2 | |
| 128 m2 | |
| 98 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 24 meters so the equation becomes: 2w + 2h = 24.
Putting these two equations together and solving for width (w):
2w + 2h = 24
w + h = \( \frac{24}{2} \)
w + h = 12
w = 12 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 12 - 2w
3w = 12
w = \( \frac{12}{3} \)
w = 4
Since h = 2w that makes h = (2 x 4) = 8 and the area = h x w = 4 x 8 = 32 m2
What is \( \sqrt{\frac{9}{25}} \)?
| \(\frac{5}{6}\) | |
| \(\frac{5}{7}\) | |
| \(\frac{3}{4}\) | |
| \(\frac{3}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{9}{25}} \)
\( \frac{\sqrt{9}}{\sqrt{25}} \)
\( \frac{\sqrt{3^2}}{\sqrt{5^2}} \)
\(\frac{3}{5}\)
A triathlon course includes a 200m swim, a 50.7km bike ride, and a 8.5km run. What is the total length of the race course?
| 61.2km | |
| 59.2km | |
| 59.4km | |
| 44.2km |
To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 200 meters to kilometers, divide the distance by 1000 to get 0.2km then add the remaining distances:
total distance = swim + bike + run
total distance = 0.2km + 50.7km + 8.5km
total distance = 59.4km
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 35,000 seats in a stadium are filled, how many home fans are in attendance?
| 29,167 | |
| 30,000 | |
| 24,667 | |
| 40,000 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
35,000 fans x \( \frac{5}{6} \) = \( \frac{175000}{6} \) = 29,167 fans.
What is the greatest common factor of 40 and 36?
| 4 | |
| 11 | |
| 33 | |
| 24 |
The factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40] and the factors of 36 are [1, 2, 3, 4, 6, 9, 12, 18, 36]. They share 3 factors [1, 2, 4] making 4 the greatest factor 40 and 36 have in common.