ASVAB Arithmetic Reasoning Practice Test 277979 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

What is 2z2 - 5z2?

71% Answer Correctly
7z4
-3z2
7z2
3z2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

2z2 - 5z2
(2 - 5)z2
-3z2


2

If \( \left|x - 6\right| \) + 2 = 8, which of these is a possible value for x?

62% Answer Correctly
21
-4
8
12

Solution

First, solve for \( \left|x - 6\right| \):

\( \left|x - 6\right| \) + 2 = 8
\( \left|x - 6\right| \) = 8 - 2
\( \left|x - 6\right| \) = 6

The value inside the absolute value brackets can be either positive or negative so (x - 6) must equal + 6 or -6 for \( \left|x - 6\right| \) to equal 6:

x - 6 = 6
x = 6 + 6
x = 12
x - 6 = -6
x = -6 + 6
x = 0

So, x = 0 or x = 12.


3

Which of the following is not a prime number?

65% Answer Correctly

5

9

2

7


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


4

Solve 4 + (3 + 3) ÷ 4 x 4 - 22

52% Answer Correctly
6
4\(\frac{1}{2}\)
1
\(\frac{2}{7}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (3 + 3) ÷ 4 x 4 - 22
P: 4 + (6) ÷ 4 x 4 - 22
E: 4 + 6 ÷ 4 x 4 - 4
MD: 4 + \( \frac{6}{4} \) x 4 - 4
MD: 4 + \( \frac{24}{4} \) - 4
AS: \( \frac{16}{4} \) + \( \frac{24}{4} \) - 4
AS: \( \frac{40}{4} \) - 4
AS: \( \frac{40 - 16}{4} \)
\( \frac{24}{4} \)
6


5

The __________ is the greatest factor that divides two integers.

67% Answer Correctly

greatest common factor

greatest common multiple

absolute value

least common multiple


Solution

The greatest common factor (GCF) is the greatest factor that divides two integers.