| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
If all of a roofing company's 8 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 3 | |
| 2 | |
| 9 | |
| 8 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 4 crews so there are \( \frac{8}{4} \) = 2 workers on a crew. 8 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 8 x 2 = 16 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 16 - 8 = 8 new staff for the busy season.
If the ratio of home fans to visiting fans in a crowd is 5:1 and all 48,000 seats in a stadium are filled, how many home fans are in attendance?
| 37,600 | |
| 24,667 | |
| 31,500 | |
| 40,000 |
A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:
48,000 fans x \( \frac{5}{6} \) = \( \frac{240000}{6} \) = 40,000 fans.
What is \( \frac{-7y^8}{7y^4} \)?
| -y-4 | |
| -y4 | |
| -y\(\frac{1}{2}\) | |
| -y12 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-7y^8}{7y^4} \)
\( \frac{-7}{7} \) y(8 - 4)
-y4
What is the distance in miles of a trip that takes 1 hour at an average speed of 45 miles per hour?
| 210 miles | |
| 385 miles | |
| 100 miles | |
| 45 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 45mph \times 1h \)
45 miles
Simplify \( \sqrt{12} \)
| 3\( \sqrt{6} \) | |
| 2\( \sqrt{3} \) | |
| 4\( \sqrt{3} \) | |
| 5\( \sqrt{3} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{12} \)
\( \sqrt{4 \times 3} \)
\( \sqrt{2^2 \times 3} \)
2\( \sqrt{3} \)