ASVAB Arithmetic Reasoning Practice Test 278252 Results

Your Results Global Average
Questions 5 5
Correct 0 3.13
Score 0% 63%

Review

1

If all of a roofing company's 8 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?

55% Answer Correctly
3
2
9
8

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 4 crews so there are \( \frac{8}{4} \) = 2 workers on a crew. 8 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 8 x 2 = 16 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 16 - 8 = 8 new staff for the busy season.


2

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 48,000 seats in a stadium are filled, how many home fans are in attendance?

50% Answer Correctly
37,600
24,667
31,500
40,000

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

48,000 fans x \( \frac{5}{6} \) = \( \frac{240000}{6} \) = 40,000 fans.


3

What is \( \frac{-7y^8}{7y^4} \)?

60% Answer Correctly
-y-4
-y4
-y\(\frac{1}{2}\)
-y12

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{-7y^8}{7y^4} \)
\( \frac{-7}{7} \) y(8 - 4)
-y4


4

What is the distance in miles of a trip that takes 1 hour at an average speed of 45 miles per hour?

87% Answer Correctly
210 miles
385 miles
100 miles
45 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 45mph \times 1h \)
45 miles


5

Simplify \( \sqrt{12} \)

62% Answer Correctly
3\( \sqrt{6} \)
2\( \sqrt{3} \)
4\( \sqrt{3} \)
5\( \sqrt{3} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{12} \)
\( \sqrt{4 \times 3} \)
\( \sqrt{2^2 \times 3} \)
2\( \sqrt{3} \)